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=Y^2-200Y-480000
We move all terms to the left:
-(Y^2-200Y-480000)=0
We get rid of parentheses
-Y^2+200Y+480000=0
We add all the numbers together, and all the variables
-1Y^2+200Y+480000=0
a = -1; b = 200; c = +480000;
Δ = b2-4ac
Δ = 2002-4·(-1)·480000
Δ = 1960000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1960000}=1400$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-1400}{2*-1}=\frac{-1600}{-2} =+800 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+1400}{2*-1}=\frac{1200}{-2} =-600 $
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